Lemma 3.1 — structure of finite tame quotients #
Paper Lemma 3.1: In every finite quotient generated by s, t with t^s = t^2, the element
t has odd order, and the quotient has the form C_e ⋊ C_n (e odd) with s⁻¹ t s = t^2.
Every normal 2-subgroup of such a quotient is central and lies in the unramified cyclic
direction.
Here the paper's t^s = t^2 means s⁻¹ * t * s = t^2 (right-conjugation convention).
The first assertion — t has odd order — is elementary and is proved in full below.
The further claims used by the formalization — normality of ⟨t⟩ and centrality of normal
2-subgroups — are also proved below. The explicit C_e ⋊ C_n decomposition is not separately
packaged because no downstream theorem consumes it.
Iterated conjugation: (sⁿ)⁻¹ t sⁿ = t^(2ⁿ), from the tame relation s⁻¹ t s = t².
Lemma 3.1 (first assertion). If a finite group is generated by s, t with the tame
relation s⁻¹ t s = t² (so in particular s has finite order), then t has odd order.
For an element t of odd order, ⟨t²⟩ = ⟨t⟩ (squaring is an automorphism of ⟨t⟩).
The cyclic subgroup ⟨t⟩ is normal in G = ⟨s, t⟩.
The proof uses zpowers_sq_eq_of_odd: conjugation by s⁻¹ is the automorphism
MulAut.conj s⁻¹,
and (MulAut.conj s⁻¹) t = s⁻¹ t s = t², so (⟨t⟩).map (conj s⁻¹) = ⟨t²⟩ = ⟨t⟩ (odd order). Hence
s (and trivially t) lie in (⟨t⟩).normalizer; since ⟨s,t⟩ = ⊤, the normalizer is ⊤, i.e.
⟨t⟩ is normal.
Lemma 3.1 (normal 2-subgroups are central). Every normal 2-subgroup N of a finite tame
quotient ⟨s,t | s⁻¹ t s = t²⟩ is central.
Key idea: N ⊓ ⟨t⟩ = ⊥ (coprime orders), so for n ∈ N the commutator ⁅n,s⁆ lies in N
(normality) and in ⟨t⟩ (the quotient G/⟨t⟩ is cyclic, hence abelian), whence ⁅n,s⁆ = 1;
together with ⁅n,t⁆ = 1 this puts n in the centralizer of the generators {s,t}, i.e. the
centre.
Paper-tag ledger (auto-generated by paperforge; do not edit) #
- Lemma 3.1 = ⟦lem-tamefinite⟧